Obliczmy sumę
[tex]1 \frac{3}{5} + 1 \frac{2}{3} = 1 \frac{9}{15} + 1 \frac{10}{15} = 2 \frac{19}{15} = 3 \frac{4}{15} [/tex]
Obliczmy różnicę
[tex] - 4 - 1 \frac{2}{3} = - \frac{4}{1} - \frac{5}{3} = - \frac{12}{3} - \frac{5}{3} = - \frac{17}{3} = - 5 \frac{2}{3} [/tex]
Podzielmy
[tex]3 \frac{4}{15} \div (- 5 \frac{2}{3} ) = \frac{49}{15} \div (- \frac{17}{3} ) = \\ = \frac{49}{15} \times ( - \frac{3}{17} ) = \frac{49}{5} \times ( - \frac{1}{17}) = - \frac{49}{85} [/tex]
