Odpowiedź:
[tex]2,8+1\frac{1}{3}\cdot0,9=2\frac{8}{10}+\frac{\not4^2}{\not3_{1}}\cdot\frac{\not9^3}{\not10_{5}}=2\frac{4}{5}+\frac{6}{5}=2\frac{4}{5}+1\frac{1}{5}=3\frac{5}{5}=4\\\\3,6\cdot\frac{3}{5}-1\frac{1}{5}=\frac{36}{10}\cdot\frac{3}{5}-1\frac{1}{5}=\frac{18}{5}\cdot\frac{3}{5}-1\frac{1}{5}=\frac{54}{25}-1\frac{1}{5}=2\frac{4}{25}-1\frac{1}{5}=2\frac{4}{25}-1\frac{5}{25}=\\\\=1\frac{29}{25}-1\frac{5}{25}=\frac{24}{25}[/tex]
