[tex]f(x)=\frac{-2x+2}{x+1}=\frac{-2(x+1)+4}{x+1}=\frac{-2(x+1)}{x+1}+\frac{4}{x+1}=-2+\frac{4}{x+1}\\a=4>0\\f(x)\nearrow \ \text{dla }x\in(-\infty,-1)\\f(x)\searrow \ \text{dla }x\in(-1,+\infty)[/tex]
