Odpowiedź :
[tex]53\frac{2}{7}-\frac{1,05}{-4\frac{1}{10}-3,25}=53\frac{2}{7}-\frac{1,05}{-4,1-3,25}=53\frac{2}{7}-\frac{1,05}{-7,35}=\\\\=53\frac{2}{7}+\frac{105 }{100}: \frac{735 }{100}=53\frac{2}{7}+\frac{\not{105}^1 }{\not{100}^1} * \frac{\not{100}^1}{\not{735}^7 } =53\frac{2}{7}+\frac{1}{7}=53\frac{3}{7}[/tex]
Odpowiedź:
[tex]53\frac{2}{7} -\frac{1,05}{-4\frac{1}{10}-3,25} =53\frac{2}{7} -\frac{1,05}{-4,1-3,25} =53\frac{2}{7} -\frac{1,05}{-7,35}=53\frac{2}{7} +\frac{3}{21}=53\frac{2}{7} +\frac{1}{7}=53\frac{3}{7}[/tex]
Szczegółowe wyjaśnienie: