Odpowiedź:
[tex]a)\ \ (\sqrt{2}+3)(\sqrt{2}-1)=2-\sqrt{2}+3\sqrt{2}-3=-1+2\sqrt{2}\\\\b)\ \ (\sqrt{5}-2)(\sqrt{5}-3)=5-3\sqrt{5}-2\sqrt{5}+6=11-5\sqrt{5}\\\\e)\ \ (\sqrt{3}+\sqrt{2})(\sqrt{3}+\sqrt{2}-1)=3+\sqrt{6}-\sqrt{3}+\sqrt{6}+2-\sqrt{2}=5+2\sqrt{6}-\sqrt{3}-\sqrt{2}\\\\f)\ \ (\sqrt{3}-\sqrt{2})(\sqrt{6}-\sqrt{3}+\sqrt{2})=\sqrt{18}-3+\sqrt{6}-\sqrt{12}+\sqrt{6}-2=\\\\=\sqrt{9\cdot2}-5+2\sqrt{6}-\sqrt{4\cdot3}=3\sqrt{2}-5+2\sqrt{6}-2\sqrt{3}[/tex]
