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proszę o rozwiązanie szybki

Proszę O Rozwiązanie Szybki class=

Odpowiedź :

Odpowiedź:

Szczegółowe wyjaśnienie:

a)12,5*5*2,5=156,25

[tex]3,75+0,28*1\frac{11}{14} = 3,75+0,5=4,25[/tex]

b)[tex]5,7:(\frac{38}{5}-3,8)= 5,7:3,8=1,5[/tex]

[tex]4,08-2,08*\frac{25}{13}= 4,08-4=0,08[/tex]

c)2,5*4,5-5,85*10/9=11,25-6,5=4,75

[tex]2,5*1,3+\frac{39}{8}*\frac{4}{5} = 3,25+3,9=7,15[/tex]

d) [tex]3*\frac{25}{9} -2*\frac{1}{8}=\frac{25}{3} -\frac{1}{4}= \frac{97}{12}[/tex]

[tex]0,2^{2}-0,04= 0[/tex]

Domiviz

a)

[tex]12\frac{1}{2}:\frac{1}{5}*2,5= \frac{25}{2}*5*\frac{5}{2}=\frac{625}{4}=156\frac{1}{4}[/tex]

[tex]3\frac{3}{4}+0,28*1\frac{11}{14}=\frac{15}{4}+\frac{7}{25}*\frac{11}{14}=\frac{15}{4}+\frac{1}{25}*\frac{11}{2}=\frac{15}{4}+\frac{11}{50}=\frac{397}{100}=3\frac{97}{100}[/tex]

b)

[tex]5,7:(5\frac{3}{7}-3,8)=\frac{57}{10}:(\frac{38}{7}-\frac{19}{5})=\frac{57}{10}:\frac{57}{35}=\frac{57}{10}*\frac{35}{57}=\frac{1}{2}*7=3\frac{1}{2}[/tex]

[tex]4,08-2,08:\frac{13}{25}=4,08-\frac{52}{25}*\frac{25}{13}=4,08-4=0,08[/tex]

c)

[tex]2,5*4\frac{1}{2}-5\frac{17}{20}:0,9=\frac{5}{2}*4*\frac{1}{2}-\frac{117}{20}:\frac{9}{10}=5*2*\frac{1}{2}-\frac{117}{20}*\frac{10}{9}=5-\frac{13}{2}=-\frac{3}{2}=-1\frac{1}{2}[/tex]

[tex]2\frac{1}{2}*1,3+4\frac{7}{8}:1,25=\frac{5}{2}*\frac{13}{10}+\frac{39}{8}:\frac{5}{4}=\frac{1}{2}*\frac{13}{2}+\frac{39}{8}*\frac{4}{5}=\frac{13}{4}+\frac{39}{2}*\frac{1}{5}=\frac{13}{4}+\frac{39}{10}=\frac{143}{20}=7\frac{3}{20}[/tex]

d)

[tex]3*(1\frac{2}{3} )^{2}-2*(0,5)^{3}=3*(\frac{5}{3} )^{2}-2*(\frac{1}{2} )^{3}= 3*(\frac{5}{3} )^{2}-2*2^{-3}=3*\frac{25}{9}-2^{-2}=\frac{25}{3}-\frac{1}{2^{2} } =\frac{25}{3}-\frac{1}{4}=\frac{97}{12}=8\frac{1}{12}[/tex]

[tex](5\frac{1}{4}-5,05)^{2} -\frac{1}{25}=(\frac{21}{4} -\frac{101}{20})^{2} -\frac{1}{25} =(\frac{1}{5})^{2} -\frac{1}{25}=\frac{1}{25}-\frac{1}{25}=0[/tex]

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