[tex]Dane:\\m_1 = 1 \ t = 1000 \ kg\\a_1 = 2\frac{m}{s^{2}}\\m_2 = 1,2 \ t = 1 \ 200 \ kg\\a_2 = 1,5\frac{m}{s^{2}}\\Szukane:\\F_1, F_2 = ?\\\\Rozwiazanie\\\\F = m\cdot a\\\\F_1 = m_1\cdot a_1 = 1000 \ kg\cdot2\frac{m}{s^{2}} =\boxed{2 \ 000 \ N = 2 \ kN}\\\\F_2 = m_2\cdot a_2 = 1200 \ kg\cdot 1,5\frac{m}{s^{2}} = \boxed{1 \ 800 \ N = 1,8 \ N}[/tex]
[tex]2 \ kN > 1,8 \ kN\\\\\boxed{F_1 > F_2}[/tex]
Odp. Większa siła działa na 1 samochód.
