Odpowiedź :
a) 3(4a² - 7a) + (3a² - 1) = 12a² - 21a + 3a² - 1 = 15a² - 21a - 1
b) - (x -5xy) - (-2x -xy) = -x + 5xy + 2x + xy = x + 6xy
a) 3(4a² - 7a) + (3a² - 1) = 12a² - 21a + 3a² - 1 = 15a² - 21a - 1
b) - (x -5xy) - (-2x -xy) = -x + 5xy + 2x + xy = x + 6xy