Odpowiedź :
1.
[tex]Dane:\\h = 10 \ m\\d_1 = 1000\frac{kg}{m^{3}}\\d_2 = 800\frac{kg}{m^{3}}\\d_3 = 900\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\Szukane:\\p_1, p_2, p_3 = ?\\\\Rozwiazanie\\\\p = d\cdot g \cdot h\\\\p_1 = d_1\cdot g\cdot h = 1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot 10 \ m = 100 \ 000 \ Pa = \boxed{100 \ kPa}\\\\p_2 = d_2\cdot g\cdot h = 800\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot 10 \ m = 80 \ 000 \ Pa = \boxed{80 \ kPa}[/tex]
[tex]p_3 = d_3\cdot g\cdot h = 900\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot10 \ m = 90 \ 000 \ Pa = \boxed{90 \ kPa}[/tex]
2.
[tex]Dane:\\p = 200 \ kPa = 200 \ 000 \ Pa = 200 \ 000 \ \frac{N}{m^{2}}\\d = 1000\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\Szukane:\\h = ?\\\\Rozwiazanie\\\\p = d\cdot g\cdot h \ \ /:(d\cdot g)\\\\h = \frac{p}{d\cdot g}\\\\h = \frac{200000\frac{n}{m^{2}}}{1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}}\\\\\boxed{h = 20 \ m}[/tex]
3.
[tex]Dane:\\h = 20 \ m\\p = 160 \ kPa = 160 \ 000 \ Pa = 160 \ 000 \ \frac{N}{m^{2}}\\g = 10\frac{N}{kg}\\Szukane:\\d = ?\\\\Rozwiazanie\\\\p = d\cdot g\cdot h \ \ /:(g\cdot h)\\\\d = \frac{p}{g\cdot h}\\\\d = \frac{160000\frac{N}{m^{2}}}{10\frac{N}{kg}\cdot20 \ m}\\\\\boxed{d = 800\frac{kg}{m^{3}}}[/tex]