1. mC2H6=2*12u+6*1u=30 u
Stosunek masowy:
mC:mH=24:6=4:1
24u---x%
30u---100%
x=80%C
100%-80%=20%H
2. mC4H9OH=4*12u+10*1u+16u=74 u
Stosunek masowy:
mC:mH:mO=48:10:16=24:5:8
48u---x%
74u---100%
x=64,86%C
10u---x%
74u---100%
x=13,51%H
100%-(64,86%+13,51%)=%O
%O=21,63%
3. mHCOOH=2*1u+12u+2*16u=46 u
Stosunek masowy:
mH:mC:mO=2:12:32=1:6:16
2u---x%
46u---100%
x=4,35%H
12u---x%
44u---100%
x=27,27%C
100%-(4,35%+27,27%)=%O
%O=68,38%