[tex]a)\\\\\sqrt{64}-\sqrt[3]{-27}=8-(-3)=3+3=6\\\\b)\\\\ 3\frac{1}{100}+\frac{\sqrt{225}}{5}=3*\frac{1}{10}+\frac{15}{5}=\frac{3}{10}+3=3\frac{3}{10}\\\\c)\\\\\sqrt[3]{16*\sqrt{16}}=\sqrt[3]{16*4}=\sqrt[3]{64}=4[/tex]
[tex]d)\\\\\sqrt{5\sqrt{5\sqrt{25}}}=\sqrt{5\sqrt{5*5}} =\sqrt{5\sqrt{25}}=\sqrt{5*5} = \sqrt{25}=5\\\\e)\\\\\sqrt{25}-\sqrt{9}+\sqrt{25-9}= 5-3+\sqrt{16} =2+4=6\\\\f)\\\\\sqrt{400}:\sqrt[3]{64} +\sqrt{49}=20:4+7=5+7=12[/tex]
