Odpowiedź:
[tex]a)\ \ (x+1)(x+2)(x+3)=(x^2+2x+x+2)(x+3)=(x^2+3x+2)(x+3)=\\\\=x^3+3x^2+3x^2+9x+2x+6=x^3+6x^2+11x+6\\\\\\b)\ \ (x-2)(x+5)(2x-1)=(x^2+5x-2x-10)(2x-1)=(x^2+3x-10)(2x-1)=\\\\=2x^3-x^2+6x^2-3x-20x+10=2x^3+5x^2-23x+10\\\\\\c)\ \ (x-4)(x+1)^2=(x-4)(x^2+2x+1)=x^3+2x^2+x-4x^2-8x-4=\\\\=x^3-2x^2-7x-4[/tex]
[tex]d)\ \ (2x-3)^2(x+2)=(4x^2-12x+9)(x+2)=4x^3+8x^2-12x^2-24x+9x+18=\\\\=4x^3-4x^2-15x+18[/tex]
