Odpowiedź:
[tex]a)\ \ x=1\ \ ,\ \ y=10\\\\-x-x^2y=-1-1^2\cdot10=-1-1\cdot10=-1-10=-11\\\\\\b)\ \ x=-10\ \ ,\ \ y=0,01\\\\-x-x^2y=-(-10)-(-10)^2\cdot0,01=10-100\cdot0,01=10-1=9\\\\\\c)\ \ x=-1\ \ ,\ \ y=\frac{1}{2}\\\\-x-x^2y=-(-1)-(-1)^2\cdot\frac{1}{2}=1-1\cdot\frac{1}{2}=1-\frac{1}{2}=\frac{1}{2}[/tex]
[tex]d)\ \ x=-\frac{1}{2}\ \ ,\ \ y=\frac{4}{5}\\\\-x-x^2y=-(-\frac{1}{2})-(-\frac{1}{2})^2\cdot\frac{4}{5}=\frac{1}{2}-\frac{1}{\not4}\cdot\frac{\not4}{5}=\frac{1}{2}-\frac{1}{5}=\frac{5}{10}-\frac{2}{10}=\frac{3}{10}[/tex]
