Odpowiedź:
[tex]4 {}^{2} + 5 {}^{2} = x {}^{2} [/tex]
16 + 25 = x do kwadratu
41 = x do kwadratu
x = pierwiastek z 41
[tex]y {}^{2} + 1 {}^{2} = (5 \sqrt{2}) {}^{2} [/tex]
y do kwadratu + 1 = 50
y do kwadratu = 49
y = pierwiastek z 49
y = 7
[tex]z {}^{2} + 4 {}^{2} = 7 {}^{2} [/tex]
z do kwadratu + 16 = 49
z do kwadratu = 33
z = pierwiastek z 33
