Odpowiedź:
c)
obwód
[tex]\sqrt{32}=\sqrt{16*2}=4\sqrt{2}\\ 4\sqrt{2}+4\sqrt{2}+5\sqrt{2}+\sqrt{2} = 14\sqrt{2}[/tex]
pole
[tex]0,5*(\sqrt{2}+4\sqrt{2})*4\sqrt{2} = 0.5*5\sqrt{2}*4\sqrt{2}=20[/tex]
d)
obwód
[tex]4*\sqrt{75} =4\sqrt{75}[/tex]
pole
[tex]6\sqrt{3}*8\sqrt{3}*0,5 = 72[/tex]
