Odpowiedź:
[tex]a)\\\\\sqrt{128}+\sqrt{8}=\sqrt{98}+\sqrt{18}\\\\\sqrt{64\cdot2}+\sqrt{4\cdot2}=\sqrt{49\cdot2}+\sqrt{9\cdot2}\\\\\sqrt{64}\cdot\sqrt{2}+\sqrt{4}\cdot\sqrt{2}=\sqrt{49}\cdot\sqrt{2}+\sqrt{9}\cdot\sqrt{2}\\\\8\sqrt{2}+2\sqrt{2}=7\sqrt{2}+3\sqrt{2}\\\\10\sqrt{2}=10\sqrt{2}\\\\L=P\\\\R\'owno\'s\'c\ \ prawdziwa[/tex]
[tex]b)\\\\\sqrt{72}+\sqrt{32}=\sqrt{162}+\sqrt{2}\\\\\sqrt{36\cdot2}+\sqrt{16\cdot2}=\sqrt{81\cdot2}+\sqrt{2}\\\\\sqrt{36}\cdot\sqrt{2}+\sqrt{16}\cdot\sqrt{2}=\sqrt{81}\cdot\sqrt{2}+\sqrt{2}\\\\6\sqrt{2}+4\sqrt{2}=9\sqrt{2}+\sqrt{2}\\\\10\sqrt{2}=10\sqrt{2}\\\\L=P\\\\R\'owno\'s\'c\ \ prawdziwa[/tex]
[tex]c)\\\\\sqrt{128}-\sqrt{18}=\sqrt{72}-\sqrt{2}\\\\\sqrt{64\cdot2}-\sqrt{9\cdot2}=\sqrt{36\cdot2}-\sqrt{2}\\\\\sqrt{64}\cdot\sqrt{2}-\sqrt{9}\cdot\sqrt{2}=\sqrt{36}\cdot\sqrt{2}-\sqrt{2}\\\\8\sqrt{2}-3\sqrt{2}=6\sqrt{2}-\sqrt{2}\\\\5\sqrt{2}=5\sqrt{2}\\\\L=P\\\\R\'owno\'s\'c\ \ prawdziwa[/tex]
[tex]d)\\\\\sqrt{98}-\sqrt{32}=\sqrt{162}-\sqrt{8}\\\\\sqrt{49\cdot2}-\sqrt{16\cdot2}=\sqrt{81\cdot2}-\sqrt{4\cdot2}\\\\\sqrt{49}\cdot\sqrt{2}-\sqrt{16}\cdot\sqrt{2}=\sqrt{81}\cdot\sqrt{2}-\sqrt{4}\cdot\sqrt{2}\\\\7\sqrt{2}-4\sqrt{2}=9\sqrt{2}-2\sqrt{2}\\\\3\sqrt{2}=7\sqrt{2}\\\\L\neq P\\\\R\'owno\'s\'c\ \ falszywa[/tex]
