Odpowiedź:
but-3en -2-on
CH2=CH-C-CH3
II
O
izomer :
aldehyd krotonowy
CH3 -CH=CH-CHO
4.
1. CH≡C-CH3 + H2--> CH2=CH-CH3
2. CH2=CH-CH3 +HCl-->CH3-CH(Cl)-CH3
3. CH3-CH(Cl) -CH3 + NaOH-- H2O--> CH3-CH(OH)-CH3
4. 3CH3-CH(OH)-CH3 + K2Cr2O7 +4H2SO4-->
--> 3CH3 -C -CH3 + Cr2(SO4)3 +K2SO4 +7H2O
II
O
