[tex]Dane:\\p = 100 \ hPa = 100\cdot100 \ Pa = 10 \ 000 \ Pa=10 \ 000 \ \frac{N}{m^{2}}\\d = 1000\frac{kg}{m^{3}} \ - \ gestosc \ wody\\g = 10\frac{N}{kg}\\Szukane:\\h = ?\\\\Rozwiazanie\\\\p = d\cdot g\cdot h \ \ /:(d\cdot g)\\\\h = \frac{p}{d\cdot g}\\\\h = \frac{10000 \ \frac{N}{m^{2}}}{1000\frac{kg}{m^{3}}\cdot10\frac{N}{kg}}\\\\\boxed{h = 1 \ m}[/tex]
