Zadanie 1.
[tex]P_p=\frac{a^2\sqrt3}{4}=\frac{6^2\sqrt3}{4}=\frac{36\sqrt3}{4}=9\sqrt3\ [cm^2]\\V=\frac{1}{3}P_p*H=\frac{1}{3}*9\sqrt3*4=12\sqrt3\ [cm^3][/tex]
Zadanie 2.
[tex]P_p=a^2=3^2=9\ [cm^2]\\V=\frac{1}{3}P_p*H=\frac{1}{3}*9*5=15\ [cm^3][/tex]
