Odpowiedź:
[tex]I.\ \ -7\frac{3}{5}:1,9-(-4)=-\frac{38}{5}:\frac{19}{10}+4=-\frac{\not38^2}{\not5_{1}}\cdot\frac{\not10^2}{\not19_{1}}+4=-4+4=0\\\\\\II.\ \ -1,4\cdot(-100)+10:(-\frac{1}{4})=140-10:\frac{1}{4}=140-10\cdot4=140-40=100\\\\\\III.\ \ -5:4-\frac{3}{\not8_{4} }\cdot\not2^1=-\frac{5}{4}-\frac{3}{4}=-\frac{8}{4}=-2\\\\\\IV.\ \ -6\cdot(\frac{2}{3}+1\frac{1}{6})=-6\cdot(\frac{4}{6}+1\frac{1}{6})=-6\cdot1\frac{5}{6}=-\not6\cdot\frac{11}{\not6}=-11[/tex]
[tex]I-B\ \ \ \ \ \ II-A\ \ \ \ \ \ III-D\ \ \ \ \ \ IV-E[/tex]
