Odpowiedź:
[tex]a)\\\\(x+2)(x+3)=x^2+3x+2x+6=x^2+5x+6\\\\(x-5)(x+4)=x^2+4x-5x-20=x^2-x-20\\\\\\b)\\\\(2x-4)(3x+8)=6x^2+16x-12x-32=6x^2+4x-32\\\\4(7x-2)(3x-1)=(28x-8)(3x-1)=84x^2-28x-24x+8=84x^2-52x+8\\\\\\c)\\\\3x-(x+2)(x-1)+5x(x-2)=3x-(x^2-x+2x-2)+5x^2-10x=\\\\=3x-x^2+x-2x+2+5x^2-10x=4x^2-8x+2\\\\\\8(x-3)(x+2)-2(x-5)(-x+6)-8=(8x-24)(x+2)-(2x-10)(-x+6)-8=\\\\=8x^2+16x-24x-48-(-2x^2+12x+10x-60)-8=\\\\=8x^2-8x-48-(-2x^2+22x-60)-8=8x^2-8x-48+2x^2-22x+60-8=\\\\=10x^2-30x+4[/tex]
[tex]d)\\\\x^2(x-1)-x^3(x^2+2x)=x^3-x^2-x^5-2x^4=-x^5-2x^4+x^3-x^2\\\\4(x^2-x-5)-(x-7)+5x^2-3=4x^2-4x-20-x+7+5x^2-3=9x^2-5x-16[/tex]
