[tex](1 \frac{3}{5} + 1 \frac{2}{3} ) \div ( - 4 - (-1 \frac{2}{3} )) = (1 \frac{9}{15} + 1 \frac{10}{15} ) \div ( - 4 - (-1 \frac{2}{3} )) = 2 \frac{19}{15} \div ( -4+1\frac{2}{3} )=\frac{49}{15} \div-2\frac{1}{3} =\frac{49}{15} \div -\frac{7}{3} = \frac{49}{15} \times -\frac{3}{7} = \frac{7}{5} \times -1= - \frac{7}{5} =-1\frac{2}{5}[/tex]
Myślę że pomogłem ;)
