Odpowiedź:
[tex](\frac{x-0,5}{3}+1)\cdot\frac{4}{5}+x=-2,5\\\\\frac{4}{5}(\frac{x-0,5}{3})+\frac{4}{5}+ x=-\frac{25}{10}\\\\\frac{4(x-0,5)}{5\cdot3}+\frac{4}{5}+x=-\frac{5}{2}\\\\\frac{4x-2}{15}+\frac{4}{5}+x=-\frac{5}{2}\ \ /\cdot30\\\\2(4x-2)+24+30x=-75\\\\8x-4+24+30x=-75\\\\38x+20=-75\\\\38x=-75-20\\\\38x=-95\ \ /:38\\\\x=-\frac{95}{38}\\\\x=-\frac{5}{2}\\\\x=-2\frac{1}{2}[/tex]
