klasa 7
proszę o pomoc w tym zadaniu ​


Klasa 7proszę O Pomoc W Tym Zadaniu class=

Odpowiedź :

[tex]\sqrt[3]{2\frac{10}{27}}\cdot(-3^{2}:3,6+\sqrt{5\frac{19}{25}}-1,9) = \sqrt[3]{\frac{64}{27}}\cdot(-9:\frac{36}{10}+\sqrt{\frac{144}{25}}-1,9) =\\\\\\=\frac{\sqrt[3]{64}}{\sqrt[3]{27}}\cdot(-9:\frac{18}{5}+\frac{\sqrt{144}}{\sqrt{25}}-1,9) =\frac{\sqrt[3]{4^{3}}}{\sqrt[3]{3^{3}}}\cdot(-9\cdot\frac{5}{18}+\frac{\sqrt{12^{2}}}{\sqrt{5^{2}}}-1,9) =\\\\\\=\frac{4}{3}\cdot(-2,5+\frac{12}{5}-1,9) = \frac{4}{3}\cdot(-2,5+2,4-1,9) = \frac{4}{3}\cdot(-2) = -\frac{8}{3} =\boxed{ -2\frac{2}{3}}[/tex]

[tex]\underline{Odp. \ B.}[/tex]