Ciepło właściwe ołowiu wynosi 130J/kg*K a glinu 900J/kg*K. Do obydwu substancji o masie
0,5kg dostarczono po 30kJ energii. Ile wynosi różnica temperatur po podgrzaniu.


Odpowiedź :

[tex]Dane:\\m_1 =m_2 =m = 0,5 \ kg\\Q_1 = Q_2 =Q = 30 \ kJ = 30 \ 000 \ J\\c_1 = 130\frac{J}{kg\cdot K} = 130\frac{J}{kg\cdot^{o}C}\\c_2=900\frac{J}{kg\cdot K} = 900\frac{J}{kg\cdot^{o}C}\\Szukane:\\\Delta T_1 = ?\\\Delta T_2 = ?\\\\\\Q = m\cdot c\cdot \Delta T \ \ /:(m\cdot c)\\\\\Delta T = \frac{Q}{m\cdot c}[/tex]

[tex]\Delta T_1 = \frac{Q}{m\cdot c_1}\\\\\Delta T_1 = \frac{30 000 \ J}{0,5 \ kg\cdot130\frac{J}{kg\cdot^{o}C}}\\\\\boxed{\Delta T_1 \approx461,5^{o}C}\\\\\\\Delta T_2 = \frac{Q}{m\cdot c_2}\\\\\Delta T_2 = \frac{30000 \ J}{0,5 \ kg\cdot900\frac{J}{kg\cdot^{o}C}}\\\\\boxed{\Delta T_2 \approx66,7^{o}C}[/tex]