Odpowiedź:
[tex]x\sqrt{5}+2<3x\\ \\x\sqrt{5}-3x<-2\\ \\x(\sqrt{5}-3)<-2\\\\x>-\frac{2}{\sqrt{5}-3} *\frac{\sqrt{5}+3}{\sqrt{5}+3}\\ \\x>-\frac{2(\sqrt{5}+3)}{(\sqrt{5}-3)(\sqrt{5}+3)} \\\\x>-\frac{2(\sqrt{5}+3)}{5-9}\\ \\x>-\frac{2(\sqrt{5}+3)}{-4}\\ \\x>\frac{\sqrt{5}+3}{2} \\[/tex]
x ∈ <[tex]\frac{\sqrt{5}+3}{2}[/tex], +∞>
