Odpowiedź:
[tex]\frac{3}{4-\sqrt{3} } * \frac{\sqrt{3}}{\sqrt{3}} = \frac{3\sqrt{3}}{4-3} = 3\sqrt{3}\\\\ \frac{\sqrt{2}+3 }{2\sqrt{2}-1} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{4\sqrt{2}}{2\sqrt{2}-\sqrt{2}} = \frac{4\sqrt{2}}{\sqrt{2}} = 4[/tex]
