[tex]x+1\not=0\\x\not=-1\\\\\dfrac{x+2}{x+1}\leq1\\(x+2)(x+1)\leq(x+1)^2\\x^2+x+2x+2\leq x^2+2x+1\\x\leq-1\\\\x\leq-1 \wedge x\not=-1\\x\in (-\infty,-1)[/tex]
