Odpowiedź:
a)2a+(4a-3b+5c)+(5c-2b)=2a +4a -3b +5c +5c-2b =6a-5b +10c
b) 5x+3y + ( 2y-4z) - (5y+6z)=5x+3y+2y-4z -5y -6z= 5x -10z
c) -3r-( 2r-4s-t) - (6r+5s)=-3r -2r +4s +t -6r -5s= -11r -s+t
d) 4k - (2m +n) - (-k-m) + (3m-n)= 4k -2m -n+k+m + 3m-n= 5k +2m-2n
e) 7a -(a+b+ab) + (2a-3ab)= 7a -a -b -ab +2a-3ab= 8a -b -4ab
f) 4xy + ( -2x -3y) - (-5x+y-5xy)= 4xy -2x -3y +5x -y +5xy= 9xy +3x-4y
g) 6m -( 2m² +n ) + (3m-2n-5m²)=6m -2m²-n +3m-2n -5m²=-7m²+9m-3n
h) -2t - ( 3t-t²)- ( 5s+4t)-(2t²-s)= -2t -3t +t²-5s-4t -2t²+s= -t²-9t-4s
Szczegółowe wyjaśnienie:
