[tex]a) \ [(2)^{\sqrt{3}}]^{\sqrt{3}} = 2^{\sqrt{3}\cdot\sqrt{3}} = 2^{3} = 8\\\\b) \ (9)^{\frac{1}{2}} = (3^{2})^{\frac{1}{2}} = 3^{2\cdot\frac{1}{2}} = 3^{1} = 3\\\\c) \ \sqrt{25-16} - \sqrt{64} = \sqrt{9}-\sqrt{64} = \sqrt{3^{2}}-\sqrt{8^{2}} = 3-8 = -5\\\\d) \ (0,25)^{-\frac{1}{2}} = (\frac{25}{100})^{-\frac{1}{2}} = (\frac{1}{4})^{-\frac{1}{2}}=4^{\frac{1}{2}} = (2^{2})^{\frac{1}{2}}=2^{2\cdot\frac{1}{2}} = 2^{1} = 2[/tex]
Zad. 8
[tex]a)\\2^{x} = \frac{1}{64}\\\\2^{x} = (\frac{1}{2})^{6}\\\\2^{x} = 2^{-6}\\\\\boxed{x = -6}[/tex]
[tex]b)\\|x-5| = 9\\\\x-5 = 9 \ \ \vee \ \ x-5 = -9\\\\x = 9+5 \ \ \vee \ \ x = -9+5\\\\\boxed{x = 14 \ \ \ \ \ \vee \ \ \ x = -4}[/tex]
