[tex] a=|(-0,5)^2- \frac{4}{5}:\sqrt{0,64} |=|0,25- \frac{4}{5}:0,8|=|\frac{ 25}{100}- \frac{4}{5}: \frac{8}{10}|=\\\\=|\frac{ 1}{4}- \frac{4}{5}: \frac{4}{5}|=|\frac{ 1}{4}- \frac{\not{4}^1}{\not{5}^1}* \frac{\not{5}^1}{\not{4}^1} |= |\frac{1}{4}-1|=|-\frac{3}{4}|=\frac{3}{4} [/tex]
[tex] b= 1,8* 1\frac{1}{3}+\sqrt[3]{-0,001} *9 =\frac{\not{18}^6}{\not{10}^5} *\frac{\not{4}^2}{\not{3}} -0,1*9=\frac{12}{5}-0,9=\\\\=\frac{12}{5}- \frac{9}{10}=\frac{24}{10}- \frac{9}{10}=\frac{15}{10}=\frac{3}{2}[/tex]
[tex]\frac{b}{a}=\frac{3}{2}:\frac{3}{4}=\frac{\not{3}^1}{\not{2}^1}*\frac{\not{4}^2}{\not{3}^1} =2\\\\odp.\ Liczba\ a\ jest\ 2\ razy\ mniejsza\ od\ liczby\ b.[/tex]