Odpowiedź :
1.
[tex]dla \ \ b = 3\frac{2}{5}\\\\1+2b = 1 + 2\cdot3\frac{2}{5} = 1+2\cdot\frac{17}{5} = 1+\frac{34}{5} =1+6\frac{4}{5} = \boxed{7\frac{4}{5}}[/tex]
2.
[tex]dla \ \ u = 1\frac{3}{4} \ dm\\\\Obw = 4\cdot1\frac{3}{4} = 4\cdot\frac{7}{4} =\boxed{7 \ dm}[/tex]
3.
[tex]dla \ \ a = 5\frac{1}{4}\\\\15\frac{1}{2}-a = 15\frac{2}{4}-5\frac{1}{4} = \boxed{10\frac{1}{4}}\\\\Odp. \ C.[/tex]
4.
[tex]dla \ \ n = 5\frac{1}{2}\\\\n\cdot 4 = 4n \ zl = 4\cdot5\frac{1}{2} = 4\cdot\frac{11}{2} = 2\cdot11 = \boxed{22 \ zl}[/tex]
5.
[tex]m - pomyslana \ liczba\\\\\boxed{\frac{m+m+12}{2}}[/tex]