hej ma dwa zadania pomuscie daje na naj
sprawdź się
zad 1 str 110
i zad 5 ste 110

[tex]a)\ \ 2\frac{1}{5}\cdot10+1\frac{3}{4}=\frac{11}{\not5_{1}}\cdot\not10^2+1\frac{3}{4}=11\cdot2+1\frac{3}{4}=22+1\frac{3}{4}=23\frac{3}{4}\\\\\\b)\ \ 3\frac{3}{4}+2\frac{2}{3}\cdot2\frac{1}{4}=3\frac{3}{4}+\frac{\not8^2}{\not3_{1}}\cdot\frac{\not9^3}{\not4_{1}}=3\frac{3}{4}+2\cdot3=3\frac{3}{4}+6=9\frac{3}{4} [/tex]

[tex]c)\ \ 2\frac{2}{5}\cdot1\frac{2}{3}-1\frac{5}{6}=\frac{\not12^4}{\not5_{1}}\cdot\frac{\not5^1}{\not3_{1}}-1\frac{5}{6}=4-1\frac{5}{6}=3\frac{6}{6}-1\frac{5}{6}=2\frac{1}{6} [/tex]

Paulinka9822viz Paulinka9822viz · Answer 2

zadanie

a)

[tex]2\frac{1}{5}razy10+1\frac{3}{4}=\frac{11}{5}razy\frac{10}{1}+1\frac{3}{4}=\frac{11}{1}razy\frac{2}{1}+1\frac{3}{4}=22+1\frac{3}{4}=23\frac{3}{4} [/tex]

b)

[tex]3\frac{3}{4}+2\frac{2}{3}razy2\frac{1}{4}=3\frac{3}{4}+\frac{8}{3}razy\frac{9}{4}=3\frac{3}{4}+\frac{2}{1}razy\frac{3}{1}=3\frac{3}{4}+6=9\frac{3}{4} [/tex]

c)

[tex]2\frac{2}{5}razy1\frac{2}{3}-1\frac{5}{6}=\frac{12}{5}razy\frac{5}{3}-1\frac{5}{6}=\frac{4}{1}razy\frac{1}{1}-1\frac{5}{6}=4-1\frac{5}{6}=2\frac{1}{6} [/tex]

mam nadzieje ze pomogłam