[tex]\frac{6\cdot\sqrt{2}}{2\sqrt{2}\cdot\sqrt{2}}=\frac{6\sqrt{2}}{2\cdot2}=\frac{6\sqrt{2}\div2}{4\div2}=\boxed{\frac{3\sqrt{2}}{2}}[/tex]
Odpowiedź:
[tex]\dfrac{\not6^3}{\not2_{1}\sqrt{2}}=\dfrac{3}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{3\sqrt{2}}{\sqrt{2}\cdot\sqrt{2}}=\dfrac{3\sqrt{2}}{2} [/tex]
