Zadanie 5.
a)
[tex]3\frac{1}{2}-x=1\frac{1}{4}\\
-x=1\frac{1}{4}-3\frac{1}{2}\\
x=3\frac{1}{2}-1\frac{1}{4}\\
x=3\frac{2}{4}-1\frac{1}{4}\\
x=2\frac{1}{4}[/tex]
b)
[tex]7\frac{3}{4}-y=3\frac{1}{2}\\
-y=3\frac{1}{2}-7\frac{3}{4}\\
y=7\frac{3}{4}-3\frac{1}{2}\\
y=7\frac{3}{4}-3\frac{2}{4}\\
y=4\frac{1}{4}[/tex]
c)
[tex]1\frac{1}{4}+z=4\frac{1}{2}\\
z=4\frac{1}{2}-1\frac{1}{4}\\
z=4\frac{2}{4}-1\frac{1}{4}\\
z=3\frac{1}{4}[/tex]
Zadanie 6.
a) [tex]\frac{1}{4} +\frac{2}{5} +\frac{1}{5} =\frac{1}{4} +\frac{3}{5} =\frac{5}{20} +\frac{12}{20}=\frac{17}{20}[/tex]
b) [tex]1-\frac{17}{20}=\frac{20}{20}-\frac{17}{20}=\frac{3}{20}[/tex]
c)
[tex]\frac{1}{4}=\frac{5}{20}\\
\frac{2}{5}=\frac{8}{20}\\
\frac{1}{5}=\frac{4}{20}[/tex]
Najwięcej Jaś, a najmniej Tomek.
d) Jaś wyplewił [tex]\frac{8}{20} [/tex], a Dominika z Tomkiem [tex]\frac{5}{20} +\frac{4}{20} =\frac{9}{20} [/tex], czyli więcej Dominika z Tomkiem.
Zadanie 7.
[tex]\frac{3}{5} +\frac{1}{4}=\frac{12}{20} +\frac{5}{20} =\frac{17}{20} \\
1-\frac{17}{20} =\frac{20}{20}-\frac{17}{20}=\frac{3}{20} [/tex]
Na obiad Miś zjadł [tex]\frac{3}{20}[/tex] garnuszka miodu.
