[tex]x = 9\sqrt{4}-4\sqrt{9} = 9\sqrt{2^{2}}-4\sqrt{3^{2}} = 9\cdot2 - 4\cdot3 = 18-12 = 6[/tex]
[tex]y = 9\sqrt{\frac{1}{4}}\cdot4\sqrt{\frac{1}{9}}=9\cdot4\cdot\sqrt{\frac{1}{4}\cdot\frac{1}{9}} = 36\sqrt{\frac{1}{36}} = 36\sqrt{(\frac{1}{6})^{2}} = 36\cdot\frac{1}{6} = 6[/tex]
1.
[tex]x = \sqrt{9}\cdot 4 = 3\cdot4 = 12 \neq 6[/tex]
FAŁSZ
2.
[tex]x = y\\6 = 6[/tex]
PRAWDA
