Odpowiedź :
a)
[tex]y=-(x+4)(x-1)\\ x+4=0\\ x_1=-4\\ x-1=0\\ x_2=1\\ p=\frac{-4+1}{2}=-\frac{3}{2}=-1\frac{1}{2}\\ q=-(-\frac{3}{2}+4)(-\frac{3}{2}-1)=-\frac{5}{2}*(-\frac{5}{2})=\frac{25}{4}=6\frac{1}{4}\\ W=(-1\frac{1}{2},6\frac{1}{4})[/tex]
b)
[tex]y=(\frac{1}{2}x-2)(6x+12)\\\frac{1}{2}x-2=0\\x_1=4\\6x+12=0\\x_2=-2\\p=\frac{4-2}{2}=1\\q=(\frac{1}{2}*1-2)(6*1+12)=-\frac{3}{2}*18=-27\\ W=(1,-27)[/tex]
c)
[tex]y=(2x+3)(4-3x)\\ 2x+3=0\\ x_1=-\frac{3}{2}=-1\frac{1}{2}\\ 4-3x=0\\ x_2=\frac{4}{3}=1\frac{1}{3}\\ p=\frac{-\frac{3}{2}+\frac{4}{3}}{2}=\frac{-\frac{9}{6}+\frac{8}{6}}{2}=\frac{-\frac{1}{6}}{2}=-\frac{1}{12}\\ q=(2*(-\frac{1}{12})+3)(4-3*(-\frac{1}{12}))=(-\frac{1}{6}+3)(4+\frac{1}{4})=2\frac{5}{6}*4\frac{1}{4}=\frac{17}{6}*\frac{17}{4}=\frac{289}{24}=12\frac{1}{24}\\ W=(-\frac{1}{12},12\frac{1}{24})[/tex]