Odpowiedź:
zad 1
x³-12x²+x-12=0
x²(x-12)+1(x-12)=0
(x-12)(x²+1)=0
x-12=0 v x²+1=0
x=12 brak
2x³-16x²-8x+64=0
2x²(x-8)-8(x-8)=0
(x-8)(2x²-8)=0
2(x-8)(x²-4)=0
2(x-8)(x-2)(x+2)=0
x-8=0 v x-2=0 v x+2=0
x=8 x=2 x=-2
zad 2
[tex]sin\alpha=\cfrac{3\sqrt{2}}{c}\\
\\
sin30^{o}=\cfrac{1}{2}\\
\\
\cfrac{1}{2}=\cfrac{3\sqrt{2}}{c}\\
\\
c=6\sqrt{2}
[/tex]
Szczegółowe wyjaśnienie:
