Z osią OX:
[tex]\sqrt{2} x+3-\sqrt{2}=0\\
\sqrt{2} x=-3+\sqrt{2}|:\sqrt{2}\\
x=\frac{-3+\sqrt{2}}{\sqrt{2}} *\frac{\sqrt{2}}{\sqrt{2}}=\frac{2-3\sqrt{2}}{2}[/tex]
więc szukany punkt to [tex](\frac{2-3\sqrt{2}}{2},0)[/tex]
Z osią OY:
[tex]y=\sqrt{2} *0+3-\sqrt{2}\\
y=3-\sqrt{2}[/tex]
więck szukany punkt to [tex](0,3-\sqrt{2})[/tex]
