Odpowiedź :
MHNO3= 1*1g/mol + 1*14 g/mol + 3*16 g/mol= 63 g/mol
1 mol HNO3 ------- 63 g
5 moli HNO3------- x
x= 315 g
M HNO3=1 g+14 g+3*16 g=63 g
63 g---1 mol
xg---5 mol
x=315 g
MHNO3= 1*1g/mol + 1*14 g/mol + 3*16 g/mol= 63 g/mol
1 mol HNO3 ------- 63 g
5 moli HNO3------- x
x= 315 g
M HNO3=1 g+14 g+3*16 g=63 g
63 g---1 mol
xg---5 mol
x=315 g