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[tex]a)\\\\ 4* \frac{3}{7}+\frac{11}{14}*6 = \frac{12}{7}+\frac{66}{14}= \frac{24}{14}+\frac{66}{14}=\frac{90}{14} =\frac{45}{7}=6\frac{3}{7}\\\\\frac{1}{4}*\frac{45}{7}=\frac{45}{28}=1\frac{17}{28}[/tex]
[tex] b)\\\\ ( \frac{1}{3}- \frac{1}{24})*8= ( \frac{8}{24}- \frac{1}{24})*8= \frac{7}{\not{24}^3}*\not{8}^1=\frac{7}{3}=2\frac{1}{3}\\\\\\3\frac{2}{3}*2\frac{1}{3}= \frac{11}{3}* \frac{7}{3}=\frac{77}{9} =8\frac{5}{9}[/tex]
