Odpowiedź:
[tex]a)\\\\\begin{cases}3x+2y=-2\ \ /\cdot3\\2x-3y=8\ \ /\cdot2\end{cases}\\\\\\+\begin{cases}9x+6y=-6\\4x-6y=16\end{cases}\\---------\\13x=10\ \ /:13\\\\x=\frac{10}{13}\\\\\\3\cdot\frac{10}{13}+2y=-2\\\\\frac{30}{13}+2y=-2\\\\2y=-2-\frac{30}{13}\\\\2y=-\frac{26}{13}-\frac{30}{13}\\\\2y=-\frac{56}{13}\ \ /:2\\\\y=-\frac{\not56^2^8}{13}\cdot\frac{1}{\not2_{1}}\\\\y=-\frac{28}{13}\\\\\\\begin{cases}x=\frac{10}{13}\\y=-\frac{28}{13}\end{cases} [/tex]
[tex]b)\\\\\begin{cases}\frac{1-x}{2}-\frac{y+1}{3}=1\ \ /\cdot6\\\\\frac{2x-y}{4}+\frac{y-x}{2}=7\ \ /\cdot4\end{cases}\\\\\\\begin{cases}3(1-x)-2(y+1)=6\\2x-y+2(y-x)=28\end{cases}\\\\\\\begin{cases}3-3x-2y-2=6\\2x-y+2y-2x=28\end{cases}\\\\\\\begin{cases}1-3x-2y=6\\y=28\end{cases}\\\\\\\begin{cases}-3x-2y=6-1\\y=28\end{cases}\\\\\\\begin{cases}-3x-2y=5\\y=28\end{cases} [/tex]
[tex]-3x-2\cdot28=5\\\\-3x-56=5\\\\-3x=5+56\\\\-3x=61\ \ /:3\\\\x=-\frac{61}{3}\\\\\\\begin{cases}x=-\frac{61}{3}\\y=28\end{cases} [/tex]
