Odpowiedź :
[tex]W = \dfrac{x^{4}-81}{x^{2}-6x+9} = \dfrac{(x^{2}-9)(x^{2}+9)}{(x-3)^{2}} = \dfrac{(x-3)(x+3)(x^{2}+9)}{(x-3)(x-3)} = \dfrac{(x+3)(x^{2}+9)}{x-3}=\\\\\\=\dfrac{x^{3}+3x^{2}+9x+27}{x-3}\\\\\\\boxed{Odp. \ C.}[/tex]
[tex]W = \dfrac{x^{4}-81}{x^{2}-6x+9} = \dfrac{(x^{2}-9)(x^{2}+9)}{(x-3)^{2}} = \dfrac{(x-3)(x+3)(x^{2}+9)}{(x-3)(x-3)} = \dfrac{(x+3)(x^{2}+9)}{x-3}=\\\\\\=\dfrac{x^{3}+3x^{2}+9x+27}{x-3}\\\\\\\boxed{Odp. \ C.}[/tex]