Odpowiedź:
[tex] \sqrt{1 \frac{9}{16} } \times {4}^{2} - ( \frac{1}{4} ) ^{3} = \sqrt{ \frac{25}{16} } \times 16 - \frac{1}{64} = \frac{5}{4} \times 16 - \frac{1}{64} = \frac{80}{4} - \frac{1}{64} = 20 - \frac{1}{64} = 19 \frac{64}{64} - \frac{1}{64} = 19 \frac{63}{64} [/tex]
Odp. B
