Odpowiedź:
Wyjaśnienie:
dane: x=4cm, y=A/2, t=π/6
szukane: λ
y = A*sin2π(t/T± x/λ)
A/2 = A*sin2π[(π/6)/T± x/λ]...............|:A
1/2 = sin2π(π/6T± x/λ)
sinπ/6 = sin2π(π/6T± x/λ)
π/6 = 2π(π/6T± x/λ)..................|:2π
1/12 = π/6T± x/λ
±x/λ = 1/12 - π/6T = 1-2π/12T
λ = |1-2π/12T*(±4cm)|
