Odpowiedź :
Odpowiedź:
[tex]\huge\boxed{x=20}[/tex]
Szczegółowe wyjaśnienie:
[tex]x(x-2)=(x+4)(x-5)\\\\x\cdot x-x\cdot2=x\cdot x-x\cdot5+4\cdot x-4\cdot5\\\\x^2-2x=x^2-5x+4x-20\\\\x^2-2x=x^2-x-20\\\\x^2-2x-x^2+x=-20\\\\-x=-20 \ \ /:(-1)\\\\x=20[/tex]
[tex]x(x-2) = (x+4)(x-5)\\\\x^{2}-2x = x^{2}-5x+4x-20\\\\x^{2}-2x = x^{2}-x-20\\\\x^{2}-x^{2}-2x+x = -20\\\\-x = -20 \ \ /:(-1)\\\\\boxed{x = 20}[/tex]