[tex]Dane:\\F = 150 \ N\\a = 3\frac{m}{s^{2}}\\Szukane:\\m = ?\\\\Z \ II \ zasady \ dynamiki:\\\\a =\frac{F}{m} \ \ /\cdot m\\\\a\cdot m = F \ \ /:a\\\\\underline{m = \frac{F}{a}}\\\\m = \frac{150 \ N}{3\frac{m}{s^{2}}} = \frac{150 \ \frac{kg\cdot m}{s^{2}}}{3\frac{m}{s^{2}}}\\\\\boxed{m = 50 \ kg}[/tex]
Odp. Szukana masa m = 50 kg.