Odpowiedź:
[tex]a)\ \ \dfrac{3\sqrt{5}}{2\sqrt{7}}=\dfrac{3\sqrt{5}}{2\sqrt{7}}\cdot\dfrac{\sqrt{7}}{\sqrt{7}}=\dfrac{3\sqrt{5\cdot7}}{2\cdot7}=\dfrac{3\sqrt{35}}{14}\\\\\\\\b)\ \ \dfrac{7\sqrt{3} }{4\sqrt{2}}=\dfrac{7\sqrt{3}}{4\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{7\sqrt{3\cdot2}}{4\cdot2}=\dfrac{7\sqrt{6}}{8}[/tex]
