[tex]Dane:\\m = 2 \ kg\\T_1 = 50^{o}C\\T_2 = 200^{o}C\\\Delta T = T_2 - T_1 = 200^{o}C - 50^{o}C = 150^{o}C\\Q = 138 \ kJ = 138 \ 000 \ J\\Szukane:\\c = ?\\\\c = \frac{Q}{m\cdot \Delta T}\\\\c = \frac{138000 \ J}{2 \ kg\cdot150^{o}C}\\\\\boxed{c = 460\frac{J}{kg\cdot^{o}C}}[/tex]
[tex]\underline{Odp. \ d)}[/tex]