wielomiany rozwiąż podane rownanie

Witaj :)
[tex]4x^4-x^2=0\\x^2(4x^2-1)=0\\x^2(2x-1)(2x+1)=0\iff x^2=0\ \vee \ 2x-1=0\ \vee \ 2x+1=0\\\\x^2=0\implies x=0\ \vee \ 2x-1=0\implies x=\frac{1}{2}\ \vee \ 2x+1=0\implies x=-\frac{1}{2}[/tex]
ODP.: [tex]x\in \{-\frac{1}{2};0;\frac{1}{2}\}[/tex]
ODP.: [tex]x\in \{-\frac{5}{3};-1;0;1\}[/tex]